![]() So whether positive or negative work is done depends on which force is being considered. ![]() A rough comparison of the slopes of the tangent lines in (a) at 0.25 s, 0.5 s, and 1.0 s with the values for velocity at the corresponding times indicates they are the same values. Positive work is done for the force you’re applying on it, but negative work is done by its weight (gravitational pull) because in that case the angle between the gravitational pull and the displacement is 180 degrees and cos180 -1. The slope of the position graph is the velocity. \( \newcommand\): (a) Position: x(t) versus time.
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